Quantitative Aptitude – Algebra – Inequalities – For how many integers n

December 30th, 2019 by

Quantitative Aptitude - Algebra - Inequalities - For how many integers n Quantitative Aptitude - Algebra - Inequalities Question For how many integers n, will the inequality (n – 5) (n – 10) – 3(n – 2) ≤ 0 be satisfied? Answer 11 Solution From CAT 2017 - Quantitative Aptitude - Algebra - Inequalities, we can see that, On solving the equation, we get n^2 – 18n + 56 ≤ 0 Factorize and we get, (n-4)(n-14) ≤ 0 4 ≤ n ≤ 14 No of values of n =11 Answer: 11 Download CAT 2017 Question Paper with answers and detai

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Quantitative Aptitude – Algebra – Inequalities – The number of solutions (x, y, z)

December 30th, 2019 by

Quantitative Aptitude - Algebra - Inequalities - The number of solutions (x, y, z) Quantitative Aptitude - Algebra - Inequalities Question The number of solutions (x, y, z) to the equation x – y – z = 25, where x, y, and z are positive integers such that x ≤ 40, y ≤ 12, and z ≤ 12 is A) 101 B) 99 C) 87 D) 105 Answer Option (B) Solution From CAT 2017 - Quantitative Aptitude - Algebra - Inequalities, we can see that, x = 25 + y + z. The possible values of x, y, z and the corresponding number of values of y, z are

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Quantitative Aptitude – Algebra – Inequalities – If N and x are positive integers

December 23rd, 2019 by

Quantitative Aptitude – Algebra - Inequalities – If N and x are positive integers Slot -2 – Quantitative Aptitude – Algebra - Inequalities – If N and x are positive integers If N and x are positive integers such that N^N = 2^160 and N^2 + 2^N is an integral multiple of 2^x, then the largest possible x is? Answer: 10 Solution: N^N = (2^5)^32 N^N = 32^32 N=32 32^2 + 2^32 = (2^5)^2 + 2^32 32^2 + 2^32 = 2^10 + 2^32 32^2 + 2^32 = 2^10(1 + 2^22) Hence, Largest possible value of x is 10. Other posts related to Quan

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Quantitative Aptitude – Algebra – Inequalities – The smallest integer n such that n^3

December 22nd, 2019 by

Quantitative Aptitude – Algebra - Inequalities – The smallest integer n such that n^3 Slot -2 – Quantitative Aptitude – Algebra - Inequalities – The smallest integer n such that n^3 The smallest integer n such that n^3 - 11n^2 + 32n - 28 > 0 is? Answer: 8 Solution: Given, n^3 - 11n^2 + 32n - 28 > 0 (n-7) (n-2)^2>0 Therefore n must be greater than 7. So smallest integral value of n = 8 Other posts related to Quantitative Aptitude – Modern Maths Permutation and Combination – Fundamental Principle of

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