# Quantitative Aptitude – Algebra – Functions – Let f(x) = min{2x^2,52−5x}

December 21st, 2019 by

Quantitative Aptitude – Algebra - Functions – Let f(x) = min{2x^2,52−5x} Slot -1 – Quantitative Aptitude – Algebra - Functions – Let f(x) = min{2x2,52−5x} Let f(x) = min{2x2,52−5x}, where x is any positive real number. Then the maximum possible value of f(x) is ( TITA )? Answer: 32 Solution: for maximum possible value , 2x2= 52−5x 2x2+ 5x – 52 = 0 (x -4)*(x+6.5) = 0 So x = 4 ( as x is positive real number ) Maximum possible value of f(x) = 2x2= 52−5x = 32 Other posts related to Quantitati

# Quantitative Aptitude – Algebra – Logarithms – If log(base12)⁡ 81=p then 3

December 21st, 2019 by

Quantitative Aptitude – Algebra - Logarithms – If log(base12)⁡ 81=p then 3 Slot -1 – Quantitative Aptitude – Algebra - Logarithms – If log(base12)⁡ 81=p then 3 If log(base12)⁡ 81=p then 3 { (4-p)/(4+p)} is equal to a) log (base2) 8 b) log (base4) 16 c) log (base6) 8 d) log (base6) 16 Solution: Given , log(base12)⁡ 81 = p 4 log (base12) 3 = p So 3 (4-p)/(4+p) = 3 (1- log(base12)⁡ 3 )/(1+ log(base12)⁡ 3)=3 × log(base12)⁡(12/3)/log(base12)⁡(12×3) = 3×log(base36)⁡ 4 = log(base6)