- 1
- -1
- 1/4
- 1/3
- 1/2

f(x)/g(x) ={((x^2+1)/(x^2-1))/((x+1)/(x-1))}=(x^2+1)/(x+1)^2 =1/(1+2x/(1+x^2 ))

Now as we can see for any values of x > 1 , 2x/(1+x^2 ) will be less than 2 thus f(x)/g(x) will be greater than 1/3 .

At x =1 , f(x) =1 and g(x) =3 thus f(x)/g(x) = 1/3

Thus minimum value of f(x)/g(x) = 1/3.

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