*Friday, May 18th, 2018*

A very common type of question that gets asked in various banking and management entrance exams is based upon the concept of finding out the rank of a word. In this post, I will like to discuss the concept behind the same. Let us look at the two types.

Suppose that you are given a word in which none of the letters are repeated and you asked to find out the rank of the word in a dictionary. For example, if the word which was given to you was **CAT**, it will be very easy to find out its rank. You will write down all possible combinations of the letters. Those are:

CAT, CTA, ATC, TCA, ACT, TAC

Now, you will arrange them in alphabetical order. It would become something like this:

ACT, ATC, CAT, CTA, TAC, TCA

CAT is third in the above list. So, the rank of the word CAT is 3.

But, as you might have realized by now – the problem would become extremely difficult if the word is bigger. Let us say that the word is **SBIPO**.

With just 5 letters, total possible arrangements are 5! or 120. It is not practical to write all of them down and find out the rank of the word SBIPO.

To solve questions like these, here is the process we need to follow.

**Step 1: Write down the letters in alphabetical order.**

The correct order will be B, I, O, P, S

**Step 2: Find out the number of words that start with a superior letter**

Any word starting from B will be above SBIPO. So, if we fix B at the first position, we can have 4! or 24 words.

Similarly, there will be 24 words that will start from I, 24 words that will start with O, and 24 words that will start with P.

So, total number of words that do no start with S and are above SBIPO is 4*24 = 96

**Step 3: Solve the same problem, without considering the first letter**

We need to find out the rank of BIPO

Correct order is B, I, O, P

=> BIPO will be the second word after BIOP

=> **Overall rank of the word SBIPO is 96 + 2 = 98.**

This might seem long but once you get a little bit of practice, you will be able to solve these questions in less than a minute.

Let us consider the word IBPSPO. As you can see, the word P is occurring twice in it. The process remains the same as above. However, there will be a slight difference in the way we calculate the answer.

**Step 1: Write down the letters in alphabetical order.**

The correct order is B, I, O, P, P, S

**Step 2: Find out the number of words that start with a superior letter**

Number of words that start with B will be 5!/2! = 60 (we are dividing by 2 because P is repeating itself)

**Step 3: Solve the same problem, without considering the first letter**

We have to find the rank of BPSPO

This will be the same as the rank of PSPO

Words above PSPO are the three words starting from O (and ending with PPS, OPSP, OSPP)

Also, PPOS, PPSO, and PSOP will be above PSPO.

=> PSPO will be the 7th word in the list

=> BPSPO will be the 7th word in the list

=> **Overall rank of the word IBPSPO is 60 + 7 = 67.**

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Quantitative Aptitude – Modern Maths – Progressions – Q1: If a1 = 1/(2*5), a2 = 1/(5*8), a3 = 1/(8*11),â€¦â€¦, then a1 + a2 +â€¦â€¦..+ a100 is

Quantitative Aptitude – Modern Maths – Progressions – Q2: An infinite geometric progression a1, a2, a3,â€¦ has the property that an = 3(a(n+ l) + a(n+2) +â€¦.) for every n â‰¥ 1. If the sum a1 + a2 + a3 +â€¦â€¦. = 32, then a5 is

Quantitative Aptitude – Modern Maths – Progressions – Q3: Let a1, a2, a3, a4, a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3.

Quantitative Aptitude – Modern Maths – Progressions – Q4: Let a1, a2,â€¦â€¦..a3n be an arithmetic progression with a1 = 3 and a2 = 7. If a1 + a2 + â€¦.+a3n = 1830, then what is the smallest positive integer m such that m (a1 + a2 + â€¦. + an ) > 1830?

Quantitative Aptitude – Modern Maths – Progressions – Q5: If the square of the 7th term of an arithmetic progression with positive common difference equals the product of the 3rd and 17th terms, then the ratio of the first term to the common difference is

Quantitative Aptitude – Modern Maths – P&C – Q1: How many four digit numbers, which are divisible by 6, can be formed using the digits 0, 2, 3, 4, 6, such that no digit is used more than once and 0 does not occur in the left-most position?

Quantitative Aptitude – Modern Maths – P&C – Q2: In how many ways can 8 identical pens be distributed among Amal, Bimal, and Kamal so that Amal gets at least 1 pen, Bimal gets at least 2 pens, and Kamal gets at least 3 pens?

Quantitative Aptitude – Modern Maths – P&C – Q3: In how many ways can 7 identical erasers be distributed among 4 kids in such a way that each kid gets at least one eraser but nobody gets more than 3 erasers?

Quantitative Aptitude – Modern Maths – P&C – Q4: Let AB, CD, EF, GH, and JK be five diameters of a circle with center at O. In how many ways can three points be chosen out of A, B, C, D, E, F, G, H, J, K, and O so as to form a triangle?

Quantitative Aptitude – Modern Maths – P&C – Q5

I hope that you found this post useful.

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