Quantitative Aptitude – Progression – let the m-th and n-th terms of the geometric
Slot – 2 – Quantitative Aptitude – Progression – let the m-th and n-th terms of the geometric
Q. let the m-th and n-th terms of the geometric progression be 3/4 and 12, respectively, where m
6
-4
-2
2
Answer: 3
Solution:
As per question,
mth term=ar^((m-1) )=3/4
nth term=ar^(n-1)= 12
On dividing,
r^(m-n)=1/16=4^(-2)=(-4)^(-2) = 2^-4 = (-2)^-4
Or m – n = -2
Or n –m = 2 then r = 4 or -4
m – n = -4
Or n –m = 4 then r = 2 or -2
Now to minimize r + n –m , n-m should be minimum which is 2 for which minimum r = -4
Thus required minimum value of r + n –m = -4 +2 = -2
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