Quantitative Aptitude – Number System – if x and y are positive real numbers satisfying


Slot – 1 – Quantitative Aptitude – Number System – if x and y are positive real numbers satisfying


Q. If x and y are positive real numbers satisfying x+y = 102, then the minimum possible value of 2601(1+1/x)(1+1/y) is?
Answer: 2704

Solution:
Given,
x+y = 102
we have to minimize , 2601*(1+1/x)(1+1/y)=2601(1+x)(1+y)/xy
to minimize this we have to maximize xy , which is maximum when x =y = 102/2 =51
so minimum value = 2601(1+x)(1+y)/xy = 2601(1+51)(1+51)/(51*51) = 2704


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