Quantitative Aptitude – In a group of 10 students, the mean of the lowest 9
Slot – 1 – Quantitative Aptitude – In a group of 10 students, the mean of the lowest 9
Q. In a group of 10 students, the mean of the lowest 9 scores is 42 while the mean of the
highest 9 scores is 47. For the entire group of 10 students, the maximum possible
mean exceeds the minimum possible mean by?
3
5
4
6
Answer: 4
Solution:
Sum of lowest 9 = 42*9 = 378
Sum of highest 9 = 47*9 = 423
Let the least score = a and highest score = b (also the sum of rest 8 = x)
So b –a = 423 – 378
b –a = 55
for the minimum possible mean b = 4
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