Quantitative Aptitude – Equation – If x1 = -1 and xm = xm+1


Slot – 3 – Quantitative Aptitude – Equation – If x1 = -1 and xm = xm+1


Q. If x(base 1) = -1 and x(base m) = x(base m+1) + (m+1) for every positive integer m, then x(base 100) equals?
  1. -5051
  2. -5151
  3. -5050
  4. -5150
Answer: 3

Solution:
X2 = x1 – (1+1) = -1 -2 = -3
X3 = x2 –(2+1) = – 6
X4 =x3 – (3+1) = -10
….so on
So x100 = – (1+2+3+4+…+100) = – 100/2 (1+100) = – 5050


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