# Quantitative Aptitude – Aron bought some pencils and sharpeners

## Slot – 2 – Quantitative Aptitude – Aron bought some pencils and sharpeners

Q. Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is ₹ 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is ?
1. 36
2. 33
3. 30
4. 27

Solutions:
Let the cost price of each pencil = x
the cost price of each sharpener = x+2
Let Aron bought y pencil and z sharpeners.
So as per question,
x*y + z(x+2) = x*2y + (z-10)*(x+2)
xy + zx + 2z = 2xy + zx -10x + 2z – 20
xy -10x = 20
y = (20+10x)/x = 20/x + 10
minimum value of y = 11 when x = 20
thus minimum number of pencils they bought together = y + 2y = 3y = 33

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