Quantitative Aptitude – Aron bought some pencils and sharpeners
Slot – 2 – Quantitative Aptitude – Aron bought some pencils and sharpeners
Q. Aron bought some pencils and sharpeners. Spending the same amount of money as
Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one
sharpener is ₹ 2 more than the cost of a pencil, then the minimum possible number of
pencils bought by Aron and Aditya together is ?
36
33
30
27
Answer: 33
Solutions:
Let the cost price of each pencil = x
the cost price of each sharpener = x+2
Let Aron bought y pencil and z sharpeners.
So as per question,
x*y + z(x+2) = x*2y + (z-10)*(x+2)
xy + zx + 2z = 2xy + zx -10x + 2z – 20
xy -10x = 20
y = (20+10x)/x = 20/x + 10
minimum value of y = 11 when x = 20
thus minimum number of pencils they bought together = y + 2y = 3y = 33
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