Quantitative Aptitude – A batsman played n + 2 innings and got out


Slot – 3 – Quantitative Aptitude – A batsman played n + 2 innings and got out


Q. A batsman played n + 2 innings and got out on all occasions. His average score in these n + 2 innings was 29 runs and he scored 38 and 15 runs in the last two innings. The batsman scored less than 38 runs in each of the first n innings. In these n innings, his average score was 30 runs and lowest score was x runs. The smallest possible value of x is?
  1. 1
  2. 3
  3. 4
  4. 2
Answer: 2

Solution:
Sum of all the scores In first n innings = 29(n+2) – 38 -15 = 29n +5
30n = 29n + 5
n = 5
so total score in first 5 innings = 5*30 = 150
to minimize x , the score of other 5 innings must be maximum which is 37 in each
so x + 4*37 = 150
x = 2


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