Slot – 2 – Quantitative Aptitude – Geometry – Triangle – Let ABC be a right-angled triangle
Q. Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is?
10
8√2
6√2
5
Answer: 10
Solution:
Let AB = a and AC = b
A^2 + b^2 = 400 by pythagoras
Let AP = x and BP = y, so CP= 20-y
So, by Pythagoras
X^2 + y^2 = a^2 and b^2 = x^2 + (20-y)^2
Maximum possible value of AP occurs when a = b, so a= b=10 root 2
On solving, we get AP = 10 units
Online Coaching Course for CAT 2020
a) 900+ Videos covering entire CAT syllabus b) 2 Live Classes (online) every week for doubt clarification c) Study Material & PDFs for practice and understanding d) 10 Mock Tests in the latest pattern e) Previous Year Questions solved on video