Quantitative Aptitude – Geometry – Polygons


Slot – 2 – Quantitative Aptitude – Geometry – Polygons – Let A and B be two regular polygons

Q. Let A and B be two regular polygons having a and b sides, respectively. If b = 2a and each interior angle of B is 3/2 times each interior angle of A, then each interior angle, in degrees, of a regular polygon with a + b sides is?

Answer: 150

Solution: Each interior angle of n sided polygon = (n-2)*180/n
(b-2)*180/b = 3/2 (a-2)*180/a and b = 2a
So, 2a-2/2 = (a-2)*3/2
2a – 2 = 3a – 6
a = 4 and b = 8
So, a + b = 12, a 12 sided polygon
Each interior angle = (12-2)*180/12 = 150 degrees

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