Quantitative Aptitude – Arithmetic – TSD


Slot – 1 – Quantitative Aptitude – Arithmetic – TSD – In a race of three horses, the first beat

Q. In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse?

Answer: 880

Solution: Let the length of race = x
When the first beat the second by 11 metres and the third by 90 metres, distance traveled by 2nd and 3rd horse at that time will be x -11 and x -90 respectively.
When the second beat the third by 80 metres traveled by 2nd and 3rd horse at that time will be x and x -80 respectively.
Ratio of speed of 2nd and 3rd horse = ratio of distance traveled = (x-11)/(x-90) = x/(x-80)
(x-11)*(x-80) = x(x-90)
By solving we get x = 880

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