Quantitative Aptitude – Arithmetic – TSD

Slot – 2 – Quantitative Aptitude – Arithmetic – TSD – A cyclist leaves A at 10 am and reaches

Q. A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motor cycle leaves A and moves towards B. Forty-five such motor cycles reach B by 11 am. All motor cycles have the same speed. If the cyclist had doubled his speed, how many motor cycles would have reached B by the time the cyclist reached B?
  1. 15
  2. 23
  3. 20
  4. 22
Answer: 15

Solution: Let speed of motor cycles be m and that of cyclist be c.
Since there are 45 motorcycles reaching in 1 hour, so the latest motorcycle must start by 10:15 from A.
Now, cyclist doubles its speed, so it reaches B at 10:30, so maximum motorcycles that can start are from 10:01 to 10:15, so 15 is the correct answer.

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