# Quantitative Aptitude – Arithmetic – Mixture – The strength of a salt solution is p%

## The strength of a salt solution is p% – Video Solution

Q. The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A is
1. 12
2. 15
3. 14
4. 13

Solution: Volume of solution in each vessels = 500ml
Salt in each vessels , in A = 10% of 500 = 50 ml
In B = 22 % of 500 = 110 ml
In C = 32% of 500 = 160 ml
When 100 ml of the solution in vessel A is transferred to vessel B, salt in B = 110 + 10% of 100 = 110 + 10 = 120 ml
% tage of salt in B = 120/600 = 20%
So When 100 ml of the solution in vessel B is transferred to vessel C = 160 + 20% of 100 = 160 + 20 = 180
% tage of salt in C = 180/600 *100 = 30 %
Now when 100 ml of the solution in vessel C is transferred to vessel A , volume of solution in A = 400+100 = 500
Salt in A = 10% of 400 + 30% of 100 = 40 + 30 = 70
% tage of salt in A = 70/500 *100 = 14 %

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