- 150
- 100
- 25
- 250

Or log(base5) (x + y)*(x-y) =3

Or x^2 â€“y^2 = 5^3 = 125————-1)

log(base2) y âˆ’ log(base2) x = 1 âˆ’ log(base2) 3= log(base2) 2 – log(base2) 3

log(base2) y/x = log(base2) 2/3

y/x = 2/3

y = 2x/3

from eq 1) x^2 â€“ (2x/3)^2 = 125

x^2 â€“ (4x^2/9) = 125

5x^2 = 125*9 or x^2 = 225

x = 15

y= 2x/3 = 30/3 = 10

xy = 15*10 =150

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