## Slot -1 – Quantitative Aptitude – Arithmetic – Profit and Loss – A wholesaler bought walnuts and peanuts

A wholesaler bought walnuts and peanuts, the price of walnut per kg being thrice that of peanut per kg. He then sold 8 kg of peanuts at a proﬁt of 10% and 16 kg of walnuts at a proﬁt of 20% to a shopkeeper. However, the shopkeeper lost 5 kg of walnuts and 3 kg of peanuts in transit. He then mixed the remaining nuts and sold the mixture at Rs. 166 per kg, thus making an overall proﬁt of 25%. At what price, in Rs. per kg, did the wholesaler buy the walnuts?

a) 84

b) 96

c) 86

d) 98

Solution:

let the CP of walnuts for wholesaler was 3x and that of peanuts was x so

SP of 8 kg of peanuts and 16 kg of walnuts = 8*1.1x + 16*1.2*3x = 66.4x

The shopkeeper gets 25% profit so SP = 1.25*66.4x =83x

As per question 83x = 166*(8+16 – 5-3) = 166*16

So x = 32

So CP of walnuts = 3x = 96

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## Slot -1 – Quantitative Aptitude – Arithmetic – Profit and Loss – A trader sells 10 liters of a mixture

A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a proﬁt of 10%, then the highest possible cost of paint B, in Rs. per litre, is?

a) 26

b) 22

c) 20

d) 16

Solution: let cost of paint A = x / liter

So cost of paint B = (x-8)/liter

Cost of 10 liter of the mixture = 264/1.1 = 240

Cost per liter of mixture = 240/10 = 24

For highest possible cost of paint B, both A and B should be in equal ratio , so

Cost of mixture = (x+ x -8)/2

24 = (2x -8)/2

x = 28

thus cost of paint B  = 28 -8 = 20 per liter

option c) 20 is correct

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## Slot -1 – Quantitative Aptitude – Arithmetic – Profit and Loss – Two types of tea, A and B, are mixed

Two types of tea, A and B, are mixed and then sold at Rs. 40 per kg. The profit is 10% if A and B are mixed in the ratio 3:2, and 5% if this ratio is 2:3. The cost prices, per kg, of A and B, are in the ratio?

a) 19:24
b) 18:25
c) 21:25
d) 17:25

Solution:

When A and B are mixed in the ratio 3:2, CP = (3A+2B)/(5 )=40/1.1

3A +2B = 2000/11 ——-1)

When A and B are mixed in the ratio 2:3, CP = (2A+3B)/(5 )=40/1.05

2A +3B = 20000/105 = 4000/21 ———–2)

By solving eq 1) & 2)

A = 7600/21*11 and B = 9600/21*11

Thus A:B = 19:24

Option a) 19:24 is correct.

## Online Coaching Course for CAT Exam Preparation

a) 750+ Videos covering entire CAT syllabus
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