a) Neither every member of A is in B nor every member of B is in A

b) Every member of A is in B and at least one member of B is not in A

c) Every member of B is in A.

d) At least one member of A is not in B

Given, A = 36^n â€“ 35n â€“ 1 = 36^n â€“ 1^n â€“ 35n

Since a^n â€“ b^n is divisible by a â€“ b for all positive integral values of n, So A is a

multiple of 35 for any integral value of n and B is a set containing all the

multiple of 35 including 0.

Hence, every member of A is in B but not every element of B is in A.

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