**Slot -2 – Quantitative Aptitude – Geometry – Rectangle – From a rectangle ABCD of area 768 sq cm**

**From a rectangle ABCD of area 768 sq cm, a semicircular part with diameter AB and area 72π sq cm is removed. The perimeter of the leftover portion, in cm, is?**

a) 88 + 12π

b) 82 + 24π

c) 80 + 16π

d) 86 + 8π

**Answer:** a) 88 + 12π

**Solution:**

Given area of semicircle = 72π

Or (πr^2)/2 = 72π

r = 12

So AB = 24

Thus 24×AD = 768

AD = 32

So Required perimeter = AD+CD+CB+πr = 32+24+32+12π = 88+12π

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