**Slot -1 – Quantitative Aptitude – Geometry – Polygons – In a parallelogram ABCD of area 72 sq cm**

**In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is?**

a) 24√3

b) 12√3

c) 32√3

d) 18√3

**Answer:** c) 32√3

**Solution:**

As given, Area of parallelogram ABCD = 72

So AB×AP=72

9AP=72

AP = 8 cm

in right-angled triangle APD, AP^2 + PD^2 = AD^2

So PD^2 = AD^2-AP^2 = 16^2-8^2 = 64×3

PD=8√3

Thus Area of triangle APD = 1/2 AP×PD = 1/2×8×8√3 = 32√3

## Other posts related to Quantitative Aptitude – Modern Maths

Permutation and Combination – Fundamental Principle of Counting

Permutation and Combination – Distribution of Objects

How to find Rank of a Word in Dictionary (With or Without Repetition)

Set Theory- Maximum and Minimum Values

How to solve questions based on At least n in Set Theory for CAT Exam?

Sequence and Series Problems and Concepts for CAT 2017 Exam Preparation

Basic Probability Concepts for CAT Preparation

## Online Coaching Course for CAT Exam Preparation

**a)** 750+ Videos covering entire CAT syllabus

**b)** 2 Live Classes (online) every week for doubt clarification

**c)** Study Material & PDFs for practice and understanding

**d)** 10 Mock Tests in the latest pattern

**e)** Previous Year Questions solved on video