Quantitative Aptitude – Geometry – Polygons – In a parallelogram ABCD of area 72 sq cm
Slot -1 – Quantitative Aptitude – Geometry – Polygons – In a parallelogram ABCD of area 72 sq cm
In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is?
a) 24√3
b) 12√3
c) 32√3
d) 18√3
Answer: c) 32√3
Solution:
As given, Area of parallelogram ABCD = 72
So AB×AP=72
9AP=72
AP = 8 cm
in right-angled triangle APD, AP^2 + PD^2 = AD^2
So PD^2 = AD^2-AP^2 = 16^2-8^2 = 64×3
PD=8√3
Thus Area of triangle APD = 1/2 AP×PD = 1/2×8×8√3 = 32√3
Other posts related to Quantitative Aptitude – Modern Maths
a) 1000+ Videos covering entire CAT syllabus b) 2 Live Classes (online) every week for doubt clarification c) Study Material & PDFs for practice and understanding d) 10 Mock Tests in the latest pattern e) Previous Year Questions solved on video