# Quantitative Aptitude – Geometry – Polygons – In a parallelogram ABCD of area 72 sq cm ## Slot -1 – Quantitative Aptitude – Geometry – Polygons – In a parallelogram ABCD of area 72 sq cm

In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is?
a) 24√3
b) 12√3
c) 32√3
d) 18√3

Solution: As given, Area of parallelogram ABCD = 72
So AB×AP=72
9AP=72
AP = 8 cm
in right-angled triangle APD, AP^2 + PD^2 = AD^2
So PD^2 = AD^2-AP^2 = 16^2-8^2 = 64×3
PD=8√3
Thus Area of triangle APD = 1/2 AP×PD = 1/2×8×8√3 = 32√3

## Other posts related to Quantitative Aptitude – Modern Maths

Permutation and Combination – Fundamental Principle of Counting
Permutation and Combination – Distribution of Objects
How to find Rank of a Word in Dictionary (With or Without Repetition)
Set Theory- Maximum and Minimum Values
How to solve questions based on At least n in Set Theory for CAT Exam?
Sequence and Series Problems and Concepts for CAT 2017 Exam Preparation
Basic Probability Concepts for CAT Preparation