Quantitative Aptitude – Arithmetic – Time Speed and Distance – Train T leaves station X for station


Quantitative Aptitude – Arithmetic - Time Speed and Distance – Train T leaves station X for station

Slot -1 – Quantitative Aptitude – Arithmetic – Time Speed and Distance – Train T leaves station X for station Y


Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves Y for X at 4 pm. The two trains pass each other at a station Z, where the distance between X and Z is three-fifths of that between X and Y. How many hours does train T take for its journey from X to Y? (TITA)

Answer: 15

Solution:
Let the total distance XY = 5x so XZ = 3x and YZ = 2x
Ratio of time taken by train T and train S to reach Z from their respective Station = (3x/v : 2x/3v/4)
= 9 : 8
Thus ( 9t -1 ) = 8t
t = 1
so time taken by train T to cover 3x = 9 hour
so time taken by train T to cover XY ( 5x ) = 5/3 *9 = 15 hour

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