**Slot -1 – Quantitative Aptitude – Arithmetic – Time Speed and Distance – Train T leaves station X for station Y**

**Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves Y for X at 4 pm. The two trains pass each other at a station Z, where the distance between X and Z is three-ﬁfths of that between X and Y. How many hours does train T take for its journey from X to Y? (TITA)**

**Answer:** 15

**Solution:**

Let the total distance XY = 5x so XZ = 3x and YZ = 2x

Ratio of time taken by train T and train S to reach Z from their respective Station = (3x/v : 2x/3v/4)

= 9 : 8

Thus ( 9t -1 ) = 8t

t = 1

so time taken by train T to cover 3x = 9 hour

so time taken by train T to cover XY ( 5x ) = 5/3 *9 = 15 hour

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