a) 26

b) 22

c) 20

d) 16

Solution: let cost of paint A = x / liter

So cost of paint B = (x-8)/liter

Cost of 10 liter of the mixture = 264/1.1 = 240

Cost per liter of mixture = 240/10 = 24

For highest possible cost of paint B, both A and B should be in equal ratio , so

Cost of mixture = (x+ x -8)/2

24 = (2x -8)/2

x = 28

thus cost of paint B = 28 -8 = 20 per liter

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