**Slot -1 – Quantitative Aptitude – Arithmetic – Profit and Loss – A trader sells 10 liters of a mixture**

**A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a proﬁt of 10%, then the highest possible cost of paint B, in Rs. per litre, is?**

a) 26

b) 22

c) 20

d) 16

Solution: let cost of paint A = x / liter

So cost of paint B = (x-8)/liter

Cost of 10 liter of the mixture = 264/1.1 = 240

Cost per liter of mixture = 240/10 = 24

For highest possible cost of paint B, both A and B should be in equal ratio , so

Cost of mixture = (x+ x -8)/2

24 = (2x -8)/2

x = 28

thus cost of paint B = 28 -8 = 20 per liter

**option c) 20 is correct**

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