**Slot -1 – Quantitative Aptitude – Arithmetic – Pipes and Cisterns – A tank is fitted with pipes**

**A tank is fitted with pipes, some filling it and the rest draining it. All ﬁlling pipes ﬁll at the same rate, and all draining pipes drain at the same rate. The empty tank gets completely filled in 6 hours when 6 filling and 5 draining pipes are on, but this time becomes 60 hours when 5 filling and 6 draining pipes are on. In how many hours will the empty tank get completely filled when one draining and two filling pipes are on? TITA**

**Answer:** 10

**Solution:**

Let each filling pipe alone can fill the tank in F hours and each draining tank alone can empty the tank in D hours. So

6/F-5/D=1/6———-1)

5/F-6/D=1/60———-2)

by solving the above equations, F=12 and D=15

So 2/F-1/D=2/12-1/15=1/10

Thus required time = 10/1 = 10 hours

**Answer:** 10

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