Quantitative Aptitude – Algebra – Logarithms – 1/log(base2⁡)100 -1/log(base4⁡)100 +1/log(base5⁡)100


Quantitative Aptitude – Algebra - Logarithms – 1/log(base2⁡)100 -1/log(base4⁡)100 +1/log(base5⁡)100

Slot -2 – Quantitative Aptitude – Algebra – Logarithms – 1/log(base2⁡)100 -1/log(base4⁡)100 +1/log(base5⁡)100



1/log(base2⁡)100 -1/log(base4)⁡100 +1/log(base5)⁡100 -1/log(base10)⁡100 +1/log(base20⁡)100 -1/log(base25)⁡100 +1/log(base50)⁡100 —?

a) ½
b) 10
c) -4
d) 0

Answer: a) ½

Solution:
Using log(basea)⁡b = 1/log(baseb⁡)a
1/log(base2⁡)100 -1/log(base4⁡)100 +1/log(base5⁡)100 -1/log(base10)⁡100 +1/log(base20)⁡100 -1/log(base25)⁡100 +1/log(base50)⁡100
= log(base100)⁡2- log(base100)⁡4+ log(base100⁡)5-log(base100⁡)10+ log(base100⁡)20-log(base100⁡)25+log(base100⁡)50
=log(base100)⁡ (2×5×20×50)/(4×10×25)
=log(base(10^2 ))⁡10=1/2

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