**Slot -2 – Quantitative Aptitude – Algebra – Inequalities – The smallest integer n such that n^3**

**The smallest integer n such that n^3 – 11n^2 + 32n – 28 > 0 is?**

**Answer:** 8

**Solution:**

Given, n^3 – 11n^2 + 32n – 28 > 0

(n-7) (n-2)^2>0

Therefore n must be greater than 7.

So smallest integral value of n = 8

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