Quantitative Aptitude – Algebra – Functions – Let f(x) = min{2x^2,52−5x}

Quantitative Aptitude – Algebra - Functions – Let f(x) = min{2x^2,52−5x}

Slot -1 – Quantitative Aptitude – Algebra – Functions – Let f(x) = min{2x2,52−5x}

Let f(x) = min{2x2,52−5x}, where x is any positive real number. Then the maximum possible value of f(x) is ( TITA )?

Answer: 32

Solution: for maximum possible value , 2x2= 52−5x

2x2+ 5x – 52 = 0

(x -4)*(x+6.5) = 0

So x = 4 ( as x is positive real number )

Maximum possible value of f(x) = 2x2= 52−5x = 32

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