# Logical Reasoning – Set – Fun Sports (FS) provides training in The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

Fun Sports (FS) provides training in three sports – Gilli-danda (G), Kho-Kho (K), and Ludo (L). Currently it has an enrollment of 39 students each of whom is enrolled in at least one of the three sports. The following details are known:

1. The number of students enrolled only in L is double the number of students enrolled in all the three sports.
2. There are a total of 17 students enrolled in G.
3. The number of students enrolled only in G is one less than the number of students enrolled only in L.
4. The number of students enrolled only in K is equal to the number of students who are enrolled in both K and L.
5. The maximum student enrollment is in L.
6. Ten students enrolled in G are also enrolled in at least one more sport.

Q 1. What is the minimum number of students enrolled in both G and L but not in K?

Q 2. If the numbers of students enrolled in K and L are in the ratio 19:22, then what is the number of students enrolled in L?

a) 19
b) 22
c) 17
d) 18

Q 3. Due to academic pressure, students who were enrolled in all three sports were asked to withdraw from one of the three sports. After the withdrawal, the number of students enrolled in G was six less than the number of students enrolled in L, while the number of students enrolled in K went down by one. After the withdrawal, how many students were enrolled in both G and K?

Q 4. Due to academic pressure, students who were enrolled in all three sports were asked to withdraw from one of the three sports. After the withdrawal, the number of students enrolled in G was six less than the number of students enrolled in L, while the number of students enrolled in K went down by one. After the withdrawal, how many students were enrolled in both G and L?

a) 7
b) 5
c) 8
d) 6

Solution:
Let the number of students enrolled in all the three sports = g and
The number of students enrolled only in K = a
So from point 1) The number of students enrolled only in L = 2g
And from point 3) The number of students enrolled only in  G = 2g – 1
So on the  basis of information given, following Venn Diagram can be made, From point 6) , b+c+g=10——1)
From point 2) (2g-1)+b+c+g=17——2)
From eq 1) & eq 2)
(2g-1)=7 or g=4
As total number of students = 39
So (2g-1)+b+c+g +(2g+a-g+a )=39
17+(2g+a-g+a )=39
17+4+2a=39
a = 9
So final Venn diagram will look like, As number of students in L is maximum , so 8+6-b>9+b or b<2.5
So b can be either 0, 1 or 2 .
1. Minimum number of students enrolled in both G and L but not K = 6 –b
So it will be minimum ,when b is maximum which is 2. So
Minimum number of students enrolled in both G and L but not K = 6 -2 = 4
2. As per above question maximum and minimum possible number of student in L are 23 and 21 respectively . So required ratio will be 19 : 22 if there is 22 students in L.
3. From g = 4, one person moves to (6-b), one person to b and two persons to (a-g) . after the withdrawal 4. d) 6

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