DILR – Data Interpretation – Set
The following set contains four questions related to Logical Reasoning. Choose the best answer to each question.
A company administers a written test comprising of three sections of 20 marks each – Data Interpretation (DI), Written English (WE) and General Awareness (GA), for recruitment. A composite score for a candidate (out of 80) is calculated by doubling her marks in DI and adding it to the sum of her marks in the other two sections. Candidates who score less than 70% marks in two or more sections are disqualified. From among the rest, the four with the highest composite scores are recruited. If four or less candidates qualify, all who qualify are recruited.
Ten candidates appeared for the written test. Their marks in the test are given in the table below. Some marks in the table are missing, but the following facts are known:
- No two candidates had the same composite score.
- Ajay was the unique highest scorer in WE.
- Among the four recruited, Geeta had the lowest composite score.
- Indu was recruited.
- Danish, Harini, and Indu had scored the same marks the in GA.
- Indu and Jatin both scored 100% in exactly one section and Jatin’s composite score was 10 more than Indu’s.
Q 1) Which of the following statements MUST be true?
- Jatin’s composite score was more than that of Danish?
- Indu scored less than Chetna in DI?
- Jatin scored more than Indu in GA?
a) Only 2
b) Only 1
c) Both 2 and 3
d) Both 1 and 2
Q 2) Which of the following statements MUST be FALSE?
a) Bala scored same as Jatin in DI
b) Bala’s composite score was less than that of Ester
c) Chetna scored more than Bala in DI
d) Harini’s composite score was less than that of Falak.
Q 3) If all the candidates except Ajay and Danish had different marks in DI, and Bala’s composite score was less than Chetna’s composite score, then what is the maximum marks that Bala could have scored in DI? TITA
Q 4) If all the candidates scored different marks in WE then what is the maximum marks that Harini could have scored in WE? TITA
Solution: For convenient let’s consider first letter of the name of each candidate as his/her name.
From point 4) Both I and J have a full score in exactly one score and J’s composite score was 10 more than I so I must score 20 in GA and J must score 20 in DI .
Thus if I’s score in DI is x , then or
From point 5) score of D and H in GA = 20
From point 1) & 2) score of A in WE = 20
From point 1) & 3) G’s score in WE must be 19.
Thus the following table can be obtained.
|Candidate Name||Marks out of 20||Total = 2DI + WE + GA||Recruited/Disqualified|
|B||18(or less)||9||11||56 (or less)||D|
Now B can not score 19 or 20 in DI as if he score 19 or 20 in DI then his composite score will be equal to as of E or I respectively , which is not possible. So B must score less than 19 in DI.
Question 1) correct option d)
Question 2) option a)
Question 3) As C‘s score is 54 so B’s score must be less than 54. Let B score x in DI then
As all candidate has different score in DI, So x can not be 16, 15 or 14 .
So maximum possible value of x = 13
Question 4) For maximum score H must score maximum in WE, which can be 17 (as all candidate have different score in WE so H can not score 20,19 or 18 as these scores have already been achieved by other candidates.
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