## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms. For any dorm, the estimated repair cost (in Rs. Crores) is an integer. Repairs with estimated cost Rs. 1 or 2 Crores are considered light repairs, repairs with estimated cost Rs. 3 or 4 are considered moderate repairs and repairs with estimated cost Rs. 5 or 6 Crores are considered extensive repairs.

Further, the following are known:

1. Odd-numbered dorms do not need light repair; even-numbered dorms do not need moderate repair and dorms, whose numbers are divisible by 3, do not need extensive repair.

2. Dorms 4 to 9 all need different repair costs, with Dorm 7 needing the maximum and Dorm 8 needing the minimum

## Questions

Q1) Which of the following is NOT necessarily true?
A) Dorm 1 needs a moderate repair
B) Dorm 5 repair will cost no more than Rs. 4 Crores
C) Dorm 7 needs an extensive repair
D) Dorm 10 repair will cost no more than Rs. 4 Crores

Q2) What is the total cost of repairing the odd-numbered dorms (in Rs. Crores)?

Q3) Suppose further that: 1. 4 of the 10 dorms needing repair are women’s dorms and need a total of Rs. 20 Crores for repair. 2. Only one of Dorms 1 to 5 is a women’s dorm.

What is the cost for repairing Dorm 9 (in Rs. Crores)?

Q4) Suppose further that: 1. 4 of the 10 dorms needing repair are women’s dorms and need a total of Rs. 20 Crores for repair. 2. Only one of Dorms 1 to 5 is a women’s dorm.

Which of the following is a women’s dorm?
A) Dorm 2
B) Dorm 5
C) Dorm 8
D) Dorm 10

Q1: Option (D)
Q2: 19
Q3: 3
Q4: Option (D)

## Solutions

CAT 2017 – Data Interpretation

Q1)
CAT 2017 – Data Interpretation
As per the options, Dorm 1 needs a moderate repair is possibly true. Dorm 5 does not need more than Rs.4 crore, which is true.
Hence, Dorm 10’s repair not costing more than Rs.4 crore is not necessarily true as it may require Rs.6 crore or Rs.1 crore.
Option (D)

Q2)
CAT 2017 – Data Interpretation
As per the question, number of dorms with repair cost as 3 crores = 3
Since Dorm 1 and 2 already have the repair cost as Rs. 3 crores.
So, out of Dorm 5 and 9, only one can have the repair cost as Rs. 3 crores
Total cost = 3+3+3/4+6+4/3 = 19
Ans : 19

Q3)
CAT 2017 – Data Interpretation
4 of the 10 dorms are women’s dorms which need Rs.20 crore for repairs. As per the question, from 1 to 5 there is only one women’s dorm. This is possible with repairing costs Rs.6, Rs.6, Rs.5 and Rs.3 crore. Among the first 5, dorm 4 should be women’s dorm. Rs.6 cr dorms can only be dorm 7 and dorm 10. Rs.3 crore can be from dorm 1, 3, 5 or 9. But 1, 3 or 5 are not women’s dorm. So it has to be dorm 9.
The repair cost for dorm 9 is Rs.3 crore. So, 3 crore is the right answer.

Q4)
CAT 2017 – Data Interpretation
4 of the 10 dorms are women’s dorms which need Rs.20 crore for repairs. Also from 1 to 5 there is only one women’s dorm. This is possible with repairing costs Rs.6, Rs.6, Rs.5 and Rs.3 crore. Among the first 5, dorm 4 should be women’s dorm. Rs.6 cr dorms can only be dorm 7 and dorm 10. Rs.3 crore can be from dorm 1, 3, 5 or 9. But 1, 3 or 5 are not women’s dorm. So it has to be dorm 9.
Dorm 10 should be women’s dorm.
Option (D)

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 2: There were seven elective courses – El to E7 – running in a specific term in a college. Each of the 300 students enrolled had chosen just one elective from among these seven.
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

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## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

An old woman had the following assets:

(a) Rs. 70 lakh in bank deposits
(b) 1 house worth Rs. 50 lakh
(c) 3 flats, each worth Rs. 30 lakh
(d) Certain number of gold coins, each worth Rs. 1 lakh

She wanted to distribute her assets among her three children; Neeta, Seeta and Geeta.

The house, any of the flats or any of the coins were not to be split. That is, the house went entirely to one child; a flat went to one child and similarly, a gold coin went to one child.

## Questions

Q1) Among the three, Neeta received the least amount in bank deposits, while Geeta received the highest. The value of the assets was distributed equally among the children, as were the gold coins.

How much did Seeta receive in bank deposits (in lakhs of rupees)?
A) 30
B) 40
C) 20
D) 10

Q2) Among the three, Neeta received the least amount in bank deposits, while Geeta received the highest. The value of the assets was distributed equally among the children, as were the gold coins.

How many flats did Neeta receive?

Q3) The value of the assets distributed among Neeta, Seeta and Geeta was in the ratio of 1:2:3, while the gold coins were distributed among them in the ratio of 2:3:4. One child got all three flats and she did not get the house. One child, other than Geeta, got Rs. 30 lakh in bank deposits.

How many gold coins did the old woman have?
A) 72
B) 90
C) 180
D) 216

Q4) The value of the assets distributed among Neeta, Seeta and Geeta was in the ratio of 1:2:3, while the gold coins were distributed among them in the ratio of 2:3:4. One child got all three flats and she did not get the house. One child, other than Geeta, got Rs. 30 lakh in bank deposits.

How much did Geeta get in bank deposits (in lakhs of rupees)?

Q1: Option (C)
Q2: 2
Q3: Option (B)
Q4: 20

## Solutions

Amount in Bank Deposits = 70 lakhs
Amount for 1 house = 50 lakhs
Amount for 1 flat = 30 lakhs
Amount for 3 flats = 90 lakhs
Number of gold coins = n
Amount in gold coins = n lakhs
Total Amount = 210 + n
House will go to only one person, 1 Flat will go to only one person and 1 Gold coin will go to one person

Q1)
CAT 2017 – Data Interpretation
Assets were divided equally among the three and so were the gold coins.
Gold coins each daughter will receive = n/3
Total Amount with each person = (210 + n)/3
Total Amount with each person – Number of gold coins = 70
One child will get the house (worth Rs. 50 lakhs). Flat can’t be given to this child as it is worth 30 lakhs and limit will be exceeded. So, the child will get 50 lakhs (House) + 20 lakhs (Bank Deposits)
Second child will get 2 Flats (60 lakhs) + 10 lakhs (Bank Deposits)
Third child will get 1 Flat (30 lakhs) + 40 lakhs (Bank Deposits)
Neeta gets the minimum amount of Bank Deposit, so 2nd child will be Neeta
Geeta gets the maximum amount of Bank Deposit, so 3rd child will be Geeta
Seeta will be the 1st child
So, Seeta got Rs. 20 lakhs as Bank Deposit.
Option (C)

Q2)
CAT 2017 – Data Interpretation
We can get the answer to this question with the help of the first one.
Neeta will get 2 flats

Q3)
CAT 2017 – Data Interpretation
Total amount distributed by the old woman = Rs.70 lakh (bank deposits) + Rs.50 lakh (House) + Rs.90 lakhs (3 flats) i.e Rs.210 lakhs + Gold coins worth Rs.1 lakh each.
Ratio of distributed gold coins = 2 : 3 : 4,
Ratio of total assets distributed = 1:2:3
From both the ratios, we can see that
Seeta received 1/3 of the total property and 1/3 of the gold coins. This means her share is 1/3 (Bank deposits + house + flats) = Rs.70 lakhs.
Also, one child got all the three flats but not the house. One child other than Geeta got Rs.30 lakhs in bank deposits. From this we can conclude that Seeta cannot get all the three flats. As her share is Rs.70 lakhs + 1/3 (gold coins).
So, Seeta should receive one house and bank deposits of Rs.20 lakhs. This suggests that Neeta should get Rs.30 lakhs in bank deposits. Therefore, Geeta should get Rs.20 lakhs in bank deposits. From this, all the three flats should be received by Geeta. Let the number of gold coins received by Neeta, Seeta and Geeta be 2x, 3x and 4x respectively.
From these we’ve. (30+2x)/(70+3x) = 1/2 => x = 10
So, number of gold coins must be 90.
Option (B)

Q4)
CAT 2017 – Data Interpretation
Total amount distributed by the old woman = Rs.70 lakh (bank deposits) + Rs.50 lakh (House) + Rs.90 lakhs (3 flats) i.e Rs.210 lakhs + Gold coins worth Rs.1 lakh each
Ratio of distributed gold coins = 2 : 3 : 4,
Ratio of total assets distributed = 1:2:3
From both the ratios, we can see that
Seeta received 1/3 of the total property and 1/3 of the gold coins. This means her share is 1/3 (Bank deposits + house + flats) = Rs.70 lakhs.
Also, one child got all the three flats but not the house. One child other than Geeta got Rs.30 lakhs in bank deposits.
From this we can conclude that Seeta cannot get all the three flats. As her share is Rs.70 lakhs + 1/3 (gold coins).
So, Seeta should receive one house and bank deposits of Rs.20 lakhs. This implies Neeta should get Rs.30 lakhs in bank deposits. Hence Geeta should get Rs.20 lakhs in bank deposits.

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: There were seven elective courses – El to E7 – running in a specific term in a college. Each of the 300 students enrolled had chosen just one elective from among these seven.
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

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## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

There were seven elective courses – El to E7 – running in a specific term in a college. Each of the 300 students enrolled had chosen just one elective from among these seven. However, before the start of the term, E7 was withdrawn as the instructor concerned had left the college. The students who had opted for E7 were allowed to join any of the remaining electives. Also, the students who had chosen other electives were given one chance to change their choice. The table below captures the movement of the students from one elective to another during this process. Movement from one elective to the same elective simply means no movement. Some numbers in the table got accidentally erased; however, it is known that these were either 0 or 1.

Further, the following are known:

1. Before the change process there were 6 more students in E1 than in E4, but after the reshuffle, the number of students in E4 was 3 more than that in E1.

2. The number of students in E2 increased by 30 after the change process.

3. Before the change process, E4 had 2 more students than E6, while E2 had 10 more students than E3.

## Questions

Q1) How many elective courses among E1 to E6 had a decrease in their enrollments after the change process?
A) 4
B) 1
C) 2
D) 3

Q2) After the change process, which of the following is the correct sequence of number of students in the six electives El to E6?
A) 19, 76, 79, 21, 45, 60
B) 19, 76, 78, 22, 45, 60
C) 18, 76, 79, 23, 43, 61
D) 18, 76, 79, 21, 45, 61

Q3) After the change process, which course among El to E6 had the largest change in its enrollment as a percentage of its original enrollment?
A) E1
B) E2
C) E3
D) E6

Q4) Later, the college imposed a condition that if after the change of electives, the enrollment in any elective (other than E7) dropped to less than 20 students, all the students who had left that course will be required to re-enroll for that elective.
Which of the following is a correct sequence of electives in decreasing order of their final enrollments?

A) E2, E3, E6, E5, El, E4
B) E3, E2, E6, E5, E4, El
C) E2, E5, E3, El, E4, E6
D) E2, E3, E5, E6, El, E3

Q1: Option (C)
Q2: Option (D)
Q3: Option (D)
Q4: Option (A)

## Solutions

As per CAT 2017 – Data Interpretation – Set, we can see that
The remaining blanks can only be 0 or 1.
Based upon the conditions, we get the following solution:

Q1
As per the table above from CAT 2017 – Data Interpretation,
Courses that decreased in their enrollments after the change process are E1 and E4.
Option (C)

Q2
As per the table above from CAT 2017 – Data Interpretation, option (D) is the correct answer.

Q3
As per the table above from CAT 2017 – Data Interpretation,
% change in E6 is the maximum as it is going from 23 to 61, more than 2.5 times the original.
Option (D)

Q4
As per the table above from CAT 2017 – Data Interpretation,
Number of enrollments would change because no movement from E1 would be allowed. New numbers for E1 to E6 would be:
31
71
69
20
41
59
So, the decreasing order would be E2 E3 E6 E5 E1 E4
(Option A)

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

## Online Coaching Course for CAT Exam Preparation

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b) 2 Live Classes (online) every week for doubt clarification
c) Study Material & PDFs for practice and understanding
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## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.

Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are four types of pizzas: T-NC, T-EC, D-NC and D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties is given below:

## Questions

Q1) How many Thin Crust pizzas were to be delivered to Party 3?
A) 398
B) 162
C) 196
D) 364

Q2) How many Normal Cheese pizzas were required to be delivered to Party 1?
A) 104
B) 84
C) 16
D) 196

Q3) For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of TEC and D-EC pizzas to be delivered to Party 2?
A) 18
B) 12
C) 30
D) 24

Q4) Suppose that a T-NC pizza cost as much as a D-NC pizza, but 3/5th of the price of a D-EC pizza. A D-EC pizza costs Rs. 50 more than a T-EC pizza, and the latter costs Rs. 500.

If 25% of the Normal Cheese pizzas delivered to Party 1 were of Deep Dish variety, what was the total bill for Party 1?
A) Rs. 59480
B) Rs. 59840
C) Rs. 42520
D) Rs. 45240

Q1: Option (B)
Q2: Option (C)
Q3: Option (B)
Q4: Option (A)

## Solutions

Q1
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 0.375*800 – (0.6+0.55)*120 = 162¬
Option (B)

Q2
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 0.52*800-0.3*120-0.65*560 = 16
Option (C)

Q3
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 120*((0.55-0.3/2) – (0.45-0.3/2)) = 120*(0.4-0.3) = 12
Option (B)

Q4
As per CAT 2017 – Data Interpretation – Set,
Cost of normal cheese pizza = 3/5th of (500 + 50) = 330
Number of normal cheese pizzas from Q2 = 16
From the remaining 120 – 16 = 104 pizzas, 0.6*120 – 25% of 16 = 60 are thin crust and the remaining 44 are Deep dish
Total cost = 60*500 + 44*550 + 16*330 = 59480
Option (A)

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

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## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C). Each of these three parameters is measured on a scale of 0 to 8 (integers only). A country is then categorized based on the total score obtained by summing the scores of ail the three parameters, as shown in the following table:

Following diagram depicts the frequency distribution of the scores in S, F and C of 10 countries – Amda, Benga, Calla, Delma, Eppa, Varsa, Wanna, Xanda, Yanga and Zooma;

Further, the following are known:
1. Amda and Calls jointly have the lowest total score, 7, with identical scores in all the three parameters.
2. Zooma has a total score of 17.
3. All the 3 countries, which are categorised as happy, have the highest score in exactly one parameter.

## Questions

Q1) What is Amda’s score in F?

Q2) What is Zooma’s score in S?

Q3) Benga and Delma, two countries categorized as happy, are tied with the same total score. What is the maximum score they can have?
A) 14
B) 15
C) 16
D) 17

Q4) If Benga scores 16 and Delma scores 15, then what is the maximum number of countries with a score of 13?
A) 0
B) 1
C) 2
D) 3

Q1: 1
Q2: 6
Q3: Option (B)
Q4: Option (B)

## Solutions

Q1
CAT 2017 – Data Interpretation – Set
As per the above table, we can see that the score of Amda in F is 1

Q2
CAT 2017 – Data Interpretation – Set
As per the table, we can see that Zooma’s score in S is 6.

Q3
CAT 2017 – Data Interpretation – Set
Only two sets are possible, (7,5,3) and (5,4,6). So, the maximum score that can be attained by B and D is 15.
Option (B) is the right answer.

Q4
CAT 2017 – Data Interpretation – Set
If Benga scores 16, then the possibility is (S-5, F-5, C-6). For Delma, the possibility is (S- 7, F-5, C-3)
So, the only possibility for the score of 13 is (S-5, F-5, C-3)
Option (B) is the right answer.

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

## Online Coaching Course for CAT Exam Preparation

a) 750+ Videos covering entire CAT syllabus
b) 2 Live Classes (online) every week for doubt clarification
c) Study Material & PDFs for practice and understanding
d) 10 Mock Tests in the latest pattern
e) Previous Year Questions solved on video

## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.

For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:

1. No one is below the 80th percentile in all 3 sections.

2. 150 are at or above the 80th percentile in exactly two sections.

3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.

4. Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C: Number of candidates below 80th percentile in M = 4:2:1.

BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.

## Questions

Q1) What best can be concluded about the number of candidates sitting for the separate test for BIE who were at or above the 90th percentile overall in CET?
A) 3 or 10
B) 10
C) 5
D) 7 or 10

Q2) If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in CET is actually a multiple of 5, what is the number of candidates who are at or above the 90th percentile overall and at or above the 80th percentile in both P and M in CET?

Q3) If the number of candidates who are at or above the 90th percentile overall and also at or above the 80 th percentile in all three sections in CET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?

Q4) If the number of candidates who are at or above the 90th percentile overall and also are at or above the 80th percentile in P in CET, is more than 100, how many candidates had to sit for the separate test for BIE?
A) 299
B) 310
C) 321
D) 330

Q1: Option (A)
Q4: Option (A)

## Solutions

As per CAT 2017 – Data Interpretation – Set, we can see that, 200 candidates scored above 90th percentile overall in CET. Let the following Venn diagram represent the number of persons who scored above 80 percentile in CET in each of the three sections:

From 1, h = 0.
From 2, d + e + f = 150
From 3, a = b = c
We know, there are a total of 200 candidates,
3a + g = 200 – 150 = 50
From 4, (2a + f) : (2a + e) : (2a + d) = 4 : 2 : 1
So, 6a + (d + e + f) is divisible by 4 + 2 + 1 = 7.
Now, since d + e + f = 150, 6a + 150 is divisible by 7, i.e.,
(6a + 3) is divisible by 7.
Hence, a = 3, 10, 17,. . .
Further, since 3a + g = 50, a < 17. Hence, only two values are possible for a, 3 or 10. We can calculate the values of the other variables for the two cases. a = 3 or 10 d = 18 or 10 e = 42 or 40 f = 90 or 100 g = 41 or 20 From the candidates who are at or above 90th percentile, the candidates who are at or above 80th percentile in at least two sections are selected for AET. Hence, the candidates represented by d, e, f and g are selected for AET. BIE will consider the candidates who are appearing for AET and are at or above 80th percentile in P. Hence, BIE will consider the candidates represented by d, e and g, which can be 104 or 80. BIE will conduct a separate test for the other students who are at or above 80th percentile in P. Given that there are a total of 400 candidates at or above 80th percentile in P, and since there are 104 or 80 candidates at or above 80th percentile in P and are at or above 90th percentile overall, there must be 296 or 320 candidates at or above 80th percentile in P who scored less than 90th percentile overall.
Q1
As per CAT 2017 – Data Interpretation – Set, we can see that, the number of candidates sitting for separate test for BIE who were at or above 90th percentile in CET is either 3 or 10.
Option (A)

Q2
As per CAT 2017 – Data Interpretation – Set, we can see that, as per the given condition, g = 5k. Hence, g = 20. The number of candidates at or above 90th percentile overall and at or above 80th percentile in both P and M = e + g = 60.

Q3
As per CAT 2017 – Data Interpretation – Set, we can see that, in this case, g = 20. Number of candidates shortlisted for AET = d + e + f + g = 10 + 40 + 100 + 20 = 170

Q4
As per CAT 2017 – Data Interpretation – Set, we can see that, as per the given condition, the number of candidates at or above 90th percentile overall and at or above 80th percentile in P in CET = 104. The number of candidates who have to sit for separate test = 296 + 3 = 299
Option (A) is the right answer.

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.
Data Interpretation – Set 5: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

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## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S). 50 four-year old kids each were sampled from each of the 150 villages from NE, 250 villages from W arid 200 villages from S. It was found that of the 30000 surveyed feds 55% studied in primary schools run by government (G), 37% in private schools (P) white the remaining 8% did not go to school (O).

The kids surveyed were further divided into two groups based on whether their mothers dropped out of school before completing primary education or not. The table below gives the number of kids in different types of schools for mothers who dropped out- of school before completing primary education:

It is also known that:

1. In S, 60% of the surveyed kids were m G. Moreover, in S, all surveyed kids whose mothers had completed primary education were in school.

2. In NE, among the O kids, 50% had mothers who had dropped out before completing primary education.

3. The number of kids in G in NE was the same as the number of kids in G in W.

## Questions

Q1) What percentage of kids from S were studying in P?
A) 37%
B) 6%
C) 79%
D) 56%

Q2) Among the kids in W whose mothers had completed primary education, how many were not in school?
A) 300
B) 1200
C) 1050
D) 1500

Q3) In a follow up survey of the same kids two years later, it was found that all the kids were now in school. Of the kids who were not in school earlier, in one region, 25% were in G now, whereas the rest were enrolled in P; in the second region, all such kids were in G now; while in the third region, 50% of such kids had now joined G while the rest had joined P. As a result, in all three regions put together, 50% of the kids who were earlier out of school had joined G. It was also seen that no surveyed kid had changed schools.
What number of the surveyed kids now were in G in W?

A) 6000
B) 5250
C) 6750
D) 6300

Q4) In a follow up survey of the same kids two years later, it was found that all the kids were now in school. Of the kids who were not in school earlier, in one region, 25% were in G now, whereas the rest were enrolled in P; in the second region, all such kids were in G now; while in the third region, 50% of such kids had now joined G while the rest had joined P. As a result, in all three regions put together, 50% of the kids who were earlier out of school had joined G. It was also seen that no surveyed kid had changed schools.
What percentage of the surveyed kids in S, whose mothers had dropped out before completing primary education, were in G now?

A) 94.7%
B) 89.5%
C) 93.4%
D) Cannot be determined from the given information

Q1: Option (A)
Q2: Option (A)
Q3: Option (A)
Q4: Option (A)

## Solutions

As per CAT 2017 – Data Interpretation – Set,
Number of students from NE = 50*150 = 7500
Number of students from W = 50*250 = 12500
Number of students from S = 50*200 = 10000
55% are in G = 16500
37% are in P = 11100
8% did not go to school (O) = 2400

Q1
As per the table deduced from CAT 2017 – Data Interpretation – Set,
Total students in S = 10000
Students from S studying in P = 300 + 3400 = 3700
% = (3700/10000)*100 = 37%
Option (A) is the right answer

Q2
As per the table deduced from CAT 2017 – Data Interpretation – Set,
For W,
Kids whose mothers had completed primary education were not in school = 300
Option (A) is the right answer.

Q3
As per the table deduced from CAT 2017 – Data Interpretation – Set,
Initially, there were 2400 students who were not in school
Now, 1200 of them are in G
The only possibility is 50% of students in W
25% of students in NE
100% of students in S who were not going to school shifted to G.
So, 50% of W = (50/100)*1500 = 750
25% of NE = (25/100)*600 = 150
100% of S = (100/100)*300 = 300
Total = 1200
So, 4200 + 1050 + 750 = 6000 surveyed students were in G in W
Option (A) is the right answer.

Q4
As explained in the previous question, 300 students who were not going to school have now shifted to G.
Of the 5700 students whose mothers had dropped out in the S region, 5400 are in G.
The required percentage = (5400/5700)*100 = 94.7%
Option (A) is the right answer.

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.
Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.
Data Interpretation – Set 5: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 6: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).

## Online Coaching Course for CAT Exam Preparation

a) 750+ Videos covering entire CAT syllabus
b) 2 Live Classes (online) every week for doubt clarification
c) Study Material & PDFs for practice and understanding
d) 10 Mock Tests in the latest pattern
e) Previous Year Questions solved on video