Consider three mixtures – the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1 : 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4:3:2. Then the resulting mixture has

A) The same amount of water and liquid B

B) The same amount of liquids B and C

C) More water than liquid B

D) More water than liquid A

Option (C)

From CAT 2017 – Quantitative Aptitude – Arithmetic – Mixtures, we can see that,

Ratio of water in 1st mixture = 1/3

Ratio of A in 1st mixture = 2/3

Ratio of water in 2nd mixture = 1/4

Ratio of B in 2nd mixture = 3/4

Ratio of water in 3rd mixture = 1/5

Ratio of C in 3rd mixture = 4/5

The mixtures are divided in the ratio 4:3:2

So, water according to this composition = 4/9 * 1/3 + 3/9 * 1/4 + 2/9 * 1/5 = 149/540 = 0.27

Solution A in the composition = 4/9 * 2/3 = 8/27 = 0.29

Solution B in the composition = 3/9 * 3/4 = 9/36 = 0.25

Solution C in the composition = 2/9 * 4/5 = 8/45 = 0.17

We can see that Option C is correct

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