If x + 1 = x^2 and x > 0, then 2x^4 is

A) 6 + 4âˆš5

B) 3 + 5âˆš5

C) 5 + 3âˆš5

D) 7 + 3âˆš5

Option (D)

As per CAT 2017 – Quantitative Aptitude – Algebra – Quadratic Equation, we can see that

x+1=x^2

Find out the roots of x = [1+/- root(5)]/2

X2 = [3 +/- âˆš5]/2

X4 = [7 +/-3âˆš5]/2

2×4 = 7 +/- 3âˆš5

As the only option is 7 + 3âˆš5 So, we go with that.

Option (D)

Quantitative Aptitude – Algebra – Quadratic Equations – Ques: The minimum possible value of the sum of the squares of the roots of the equation x^2 + (a + 3)x â€“ (a + 5) = 0 is

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