# Data Interpretation – Set – Funky Pizzaria was required to supply pizzas

## DILR – Data Interpretation – Set

The following set contains four questions related to Data Interpretation. Choose the best answer to each question.

Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.

Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are four types of pizzas: T-NC, T-EC, D-NC and D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties is given below:

## Questions

Q1) How many Thin Crust pizzas were to be delivered to Party 3?
A) 398
B) 162
C) 196
D) 364

Q2) How many Normal Cheese pizzas were required to be delivered to Party 1?
A) 104
B) 84
C) 16
D) 196

Q3) For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of TEC and D-EC pizzas to be delivered to Party 2?
A) 18
B) 12
C) 30
D) 24

Q4) Suppose that a T-NC pizza cost as much as a D-NC pizza, but 3/5th of the price of a D-EC pizza. A D-EC pizza costs Rs. 50 more than a T-EC pizza, and the latter costs Rs. 500.

If 25% of the Normal Cheese pizzas delivered to Party 1 were of Deep Dish variety, what was the total bill for Party 1?
A) Rs. 59480
B) Rs. 59840
C) Rs. 42520
D) Rs. 45240

Q1: Option (B)
Q2: Option (C)
Q3: Option (B)
Q4: Option (A)

## Solutions

Q1
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 0.375*800 – (0.6+0.55)*120 = 162¬
Option (B)

Q2
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 0.52*800-0.3*120-0.65*560 = 16
Option (C)

Q3
As per CAT 2017 – Data Interpretation – Set,
With the original table given in the question 120*((0.55-0.3/2) – (0.45-0.3/2)) = 120*(0.4-0.3) = 12
Option (B)

Q4
As per CAT 2017 – Data Interpretation – Set,
Cost of normal cheese pizza = 3/5th of (500 + 50) = 330
Number of normal cheese pizzas from Q2 = 16
From the remaining 120 – 16 = 104 pizzas, 0.6*120 – 25% of 16 = 60 are thin crust and the remaining 44 are Deep dish
Total cost = 60*500 + 44*550 + 16*330 = 59480
Option (A)

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.
Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits
Data Interpretation – Set 3: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).
Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.
Data Interpretation – Set 5: Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET).
Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

## Online Coaching Course for CAT Exam Preparation

a) 750+ Videos covering entire CAT syllabus
b) 2 Live Classes (online) every week for doubt clarification
c) Study Material & PDFs for practice and understanding
d) 10 Mock Tests in the latest pattern
e) Previous Year Questions solved on video