**DILR – Data Interpretation – Set**

**The following set contains four questions related to Data Interpretation. Choose the best answer to each question.**

Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.

For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:

1. No one is below the 80th percentile in all 3 sections.

2. 150 are at or above the 80th percentile in exactly two sections.

3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.

4. Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C: Number of candidates below 80th percentile in M = 4:2:1.

BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.

**Questions**

**Q1) What best can be concluded about the number of candidates sitting for the separate test for BIE who were at or above the 90th percentile overall in CET?**

A) 3 or 10

B) 10

C) 5

D) 7 or 10

**Q2) If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in CET is actually a multiple of 5, what is the number of candidates who are at or above the 90th percentile overall and at or above the 80th percentile in both P and M in CET?**

**Q3) If the number of candidates who are at or above the 90th percentile overall and also at or above the 80 th percentile in all three sections in CET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?**

**Q4) If the number of candidates who are at or above the 90th percentile overall and also are at or above the 80th percentile in P in CET, is more than 100, how many candidates had to sit for the separate test for BIE?**

A) 299

B) 310

C) 321

D) 330

**Answers**

Q1: Option (A)

Q2: Answer – 60

Q3: Answer – 170

Q4: Option (A)

**Solutions**

As per CAT 2017 – Data Interpretation – Set, we can see that, 200 candidates scored above 90th percentile overall in CET. Let the following Venn diagram represent the number of persons who scored above 80 percentile in CET in each of the three sections:

From 1, h = 0.

From 2, d + e + f = 150

From 3, a = b = c

We know, there are a total of 200 candidates,

3a + g = 200 – 150 = 50

From 4, (2a + f) : (2a + e) : (2a + d) = 4 : 2 : 1

So, 6a + (d + e + f) is divisible by 4 + 2 + 1 = 7.

Now, since d + e + f = 150, 6a + 150 is divisible by 7, i.e.,

(6a + 3) is divisible by 7.

Hence, a = 3, 10, 17,. . .

Further, since 3a + g = 50, a < 17. Hence, only two values are possible for a, 3 or 10. We can calculate the values of the other variables for the two cases.
a = 3 or 10
d = 18 or 10
e = 42 or 40
f = 90 or 100
g = 41 or 20
From the candidates who are at or above 90th percentile, the candidates who are at or above 80th percentile in at least two sections are selected for AET. Hence, the candidates represented by d, e, f and g are selected for AET. BIE will consider the candidates who are appearing for AET and are at or above 80th percentile in P. Hence, BIE will consider the candidates represented by d, e and g, which can be 104 or 80.
BIE will conduct a separate test for the other students who are at or above 80th percentile in P. Given that there are a total of 400 candidates at or above 80th percentile in P, and since there are 104 or 80 candidates at or above 80th percentile in P and are at or above 90th percentile overall, there must be 296 or 320 candidates at or above 80th percentile in P who scored less than 90th percentile overall.

**Q1**

As per CAT 2017 – Data Interpretation – Set, we can see that, the number of candidates sitting for separate test for BIE who were at or above 90th percentile in CET is either 3 or 10.

Option (A)

**Q2**

As per CAT 2017 – Data Interpretation – Set, we can see that, as per the given condition, g = 5k. Hence, g = 20. The number of candidates at or above 90th percentile overall and at or above 80th percentile in both P and M = e + g = 60.

Answer: 60

**Q3**

As per CAT 2017 – Data Interpretation – Set, we can see that, in this case, g = 20. Number of candidates shortlisted for AET = d + e + f + g = 10 + 40 + 100 + 20 = 170

Answer: 170

**Q4**

As per CAT 2017 – Data Interpretation – Set, we can see that, as per the given condition, the number of candidates at or above 90th percentile overall and at or above 80th percentile in P in CET = 104. The number of candidates who have to sit for separate test = 296 + 3 = 299

Option (A) is the right answer.

## Download CAT 2017 Question Paper with answers and detailed solutions in PDF

## CAT 2017 Questions from Data Interpretation

Data Interpretation – Set 1: At a management school, the oldest 10 dorms, numbered 1 to 10, need to be repaired urgently, The following diagram represents the estimated repair costs (in Rs. Crores) for the 10 dorms.

Data Interpretation – Set 2: An old woman had the following assets: Rs. 70 lakh in bank deposits

Data Interpretation – Set 3: Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.

Data Interpretation – Set 4: There were seven elective courses – El to E7 – running in a specific term in a college.

Data Interpretation – Set 5: Simple Happiness index (SHI) of a country is computed on the basis of three parameters: social support (S), freedom to life choices (F) and corruption perception (C).

Data Interpretation – Set 6: A study to look at the early teaming of rural kids was carried out in a number of villages spanning three states, chosen from the North East (NE), the West (W) and the South (S).

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