Doubts

Moderator: ravihanda

Doubts

Postby ravihanda » Mon Aug 24, 2009 2:22 pm

Please go through the solved examples before asking a doubt.
ravihanda
 
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Re: Doubts

Postby surya1 » Mon Nov 09, 2009 9:03 am

Q) |y|=|x+1| find the no. of integral solutions
surya1
 

Re: Doubts

Postby ravihanda » Tue Nov 10, 2009 11:36 am

Surya,

I think you got the question wrong. The equation you have given has infinite many integral solutions. Please check.

x=0, y =1
x=1, y =2
x=2, y =3 and so on.
ravihanda
 
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Re: Doubts

Postby Gagan » Sun Jul 04, 2010 12:26 am

Hi Ravi,Please help me out with the below question
Find the range of x in following inequality|x-6|>|x2-5x+9|

Also can you please tell me whether we have to take the intersection of range of x from different equation or the union of the ranges
Gagan
 

Re: Doubts

Postby grimreaper » Mon Jul 05, 2010 12:16 am

Gagan wrote:Hi Ravi,Please help me out with the below question
Find the range of x in following inequality|x-6|>|x2-5x+9|

Also can you please tell me whether we have to take the intersection of range of x from different equation or the union of the ranges


ranges can be anything....provided they satisfy your initial domain......for eg... if i take |x-3| = A and i say x is greater than 3, than on solving if i arrive at a value of x lesser than 3, means no solution.....

so its the domain thats more imp

as for this Q...
notice your quad is having coef of x^2 as positive.... and D<0 so this is always greater than 0, so only condition you have to check is if x is lesser than 6 or greater...
for x greater than 6, no solution
x-6>x^2-5x+9
or x^2-6x+15<0 ... not possi...cause again D<0 so always greater than 0

for x<6
you get..

x^2-4x+3<0 implies... x belongs to (1,3) excluding 1,3 as no equality sign is there.
so your range of "x" is nothing but the domain....itself.........
had they asked range of F(x) then sub value of x and get the answer
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